1/2(6-z)=13

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Solution for 1/2(6-z)=13 equation: 



1/2(6-z)=13

We move all terms to the left:

1/2(6-z)-(13)=0



Domain of the equation: 2(6-z)!=0

z∈R



We add all the numbers together, and all the variables

1/2(-1z+6)-13=0

We multiply all the terms by the denominator


-13*2(-1z+6)+1=0

Wy multiply elements

-26z(-+1=0

We use the square of the difference formula

-26z(-1=0

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