1/2(6c+2)=2/5(5c-10)

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Solution for 1/2(6c+2)=2/5(5c-10) equation:



1/2(6c+2)=2/5(5c-10)
We move all terms to the left:
1/2(6c+2)-(2/5(5c-10))=0
Domain of the equation: 2(6c+2)!=0
c∈R
Domain of the equation: 5(5c-10))!=0
c∈R
We calculate fractions
(5c5/(2(6c+2)*5(5c-10)))+(-4c6/(2(6c+2)*5(5c-10)))=0
We calculate terms in parentheses: +(5c5/(2(6c+2)*5(5c-10))), so:
5c5/(2(6c+2)*5(5c-10))
We multiply all the terms by the denominator
5c5
We add all the numbers together, and all the variables
5c^5
We do not support ecpression: c^5

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