1/2(6x+18)-4=-1/5(20x-35)

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Solution for 1/2(6x+18)-4=-1/5(20x-35) equation: 



1/2(6x+18)-4=-1/5(20x-35)

We move all terms to the left:

1/2(6x+18)-4-(-1/5(20x-35))=0



Domain of the equation: 2(6x+18)!=0

x∈R





Domain of the equation: 5(20x-35))!=0

x∈R



We calculate fractions


(5x2/(2(6x+18)*5(20x-35)))+(-(-2x6)/(2(6x+18)*5(20x-35)))-4=0



We calculate terms in parentheses: +(5x2/(2(6x+18)*5(20x-35))), so:

5x2/(2(6x+18)*5(20x-35))

We multiply all the terms by the denominator


5x2

We add all the numbers together, and all the variables

5x^2

Back to the equation:

+(5x^2)





We calculate terms in parentheses: +(-(-2x6)/(2(6x+18)*5(20x-35))), so:

-(-2x6)/(2(6x+18)*5(20x-35))

We add all the numbers together, and all the variables

-(-2x^6)/(2(6x+18)*5(20x-35))

We multiply all the terms by the denominator


-(-2x^6)

We do not support expression: x^6

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