1/2(6x+4)-19=-1/3(21x-27)

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Solution for 1/2(6x+4)-19=-1/3(21x-27) equation: 



1/2(6x+4)-19=-1/3(21x-27)

We move all terms to the left:

1/2(6x+4)-19-(-1/3(21x-27))=0



Domain of the equation: 2(6x+4)!=0

x∈R





Domain of the equation: 3(21x-27))!=0

x∈R



We calculate fractions


(3x2/(2(6x+4)*3(21x-27)))+(-(-2x6)/(2(6x+4)*3(21x-27)))-19=0



We calculate terms in parentheses: +(3x2/(2(6x+4)*3(21x-27))), so:

3x2/(2(6x+4)*3(21x-27))

We multiply all the terms by the denominator


3x2

We add all the numbers together, and all the variables

3x^2

Back to the equation:

+(3x^2)





We calculate terms in parentheses: +(-(-2x6)/(2(6x+4)*3(21x-27))), so:

-(-2x6)/(2(6x+4)*3(21x-27))

We add all the numbers together, and all the variables

-(-2x^6)/(2(6x+4)*3(21x-27))

We multiply all the terms by the denominator


-(-2x^6)

We do not support expression: x^6

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