1/2(6x+4)=1/4(8+12x)

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Solution for 1/2(6x+4)=1/4(8+12x) equation:



1/2(6x+4)=1/4(8+12x)
We move all terms to the left:
1/2(6x+4)-(1/4(8+12x))=0
Domain of the equation: 2(6x+4)!=0
x∈R
Domain of the equation: 4(8+12x))!=0
x∈R
We add all the numbers together, and all the variables
1/2(6x+4)-(1/4(12x+8))=0
We calculate fractions
(4x1/(2(6x+4)*4(12x+8)))+(-2x6/(2(6x+4)*4(12x+8)))=0
We calculate terms in parentheses: +(4x1/(2(6x+4)*4(12x+8))), so:
4x1/(2(6x+4)*4(12x+8))
We multiply all the terms by the denominator
4x1
We add all the numbers together, and all the variables
4x
Back to the equation:
+(4x)
We calculate terms in parentheses: +(-2x6/(2(6x+4)*4(12x+8))), so:
-2x6/(2(6x+4)*4(12x+8))
We multiply all the terms by the denominator
-2x6
We add all the numbers together, and all the variables
-2x^6
We do not support expression: x^6

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