1/2(6x+4)=1/5(25x+20)

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Solution for 1/2(6x+4)=1/5(25x+20) equation: 



1/2(6x+4)=1/5(25x+20)

We move all terms to the left:

1/2(6x+4)-(1/5(25x+20))=0



Domain of the equation: 2(6x+4)!=0

x∈R





Domain of the equation: 5(25x+20))!=0

x∈R



We calculate fractions


(5x2/(2(6x+4)*5(25x+20)))+(-2x6/(2(6x+4)*5(25x+20)))=0



We calculate terms in parentheses: +(5x2/(2(6x+4)*5(25x+20))), so:

5x2/(2(6x+4)*5(25x+20))

We multiply all the terms by the denominator


5x2

We add all the numbers together, and all the variables

5x^2

Back to the equation:

+(5x^2)





We calculate terms in parentheses: +(-2x6/(2(6x+4)*5(25x+20))), so:

-2x6/(2(6x+4)*5(25x+20))

We multiply all the terms by the denominator


-2x6

We add all the numbers together, and all the variables

-2x^6

We do not support expression: x^6

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