1/2(6x+4)=7x+3x-40

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Solution for 1/2(6x+4)=7x+3x-40 equation: 



1/2(6x+4)=7x+3x-40

We move all terms to the left:

1/2(6x+4)-(7x+3x-40)=0



Domain of the equation: 2(6x+4)!=0

x∈R



We add all the numbers together, and all the variables

1/2(6x+4)-(10x-40)=0

We get rid of parentheses

1/2(6x+4)-10x+40=0

We multiply all the terms by the denominator


-10x*2(6x+4)+40*2(6x+4)+1=0

Wy multiply elements

-20x^2(6+80x(6+1=0

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