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1/2(6x-4)+2-3x=3-(4x+5)
We move all terms to the left:
1/2(6x-4)+2-3x-(3-(4x+5))=0
Domain of the equation: 2(6x-4)!=0We add all the numbers together, and all the variables
x∈R
-3x+1/2(6x-4)-(3-(4x+5))+2=0
We multiply all the terms by the denominator
-3x*2(6x-4)-((3-(4x+5)))*2(6x-4)+2*2(6x-4)+1=0
We calculate terms in parentheses: -((3-(4x+5)))*2(6x-4), so:Wy multiply elements
(3-(4x+5)))*2(6x-4
-6x^2(6-((3-(4x+5)))*2(6x-4)+4x(6+1=0
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