1/2(6x-4)+7+3x=40

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Solution for 1/2(6x-4)+7+3x=40 equation: 



1/2(6x-4)+7+3x=40

We move all terms to the left:

1/2(6x-4)+7+3x-(40)=0



Domain of the equation: 2(6x-4)!=0

x∈R



We add all the numbers together, and all the variables

3x+1/2(6x-4)-33=0

We multiply all the terms by the denominator


3x*2(6x-4)-33*2(6x-4)+1=0

Wy multiply elements

6x^2(6-66x(6+1=0

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