1/2(6x-4)+8-5=12

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Solution for 1/2(6x-4)+8-5=12 equation: 



1/2(6x-4)+8-5=12

We move all terms to the left:

1/2(6x-4)+8-5-(12)=0



Domain of the equation: 2(6x-4)!=0

x∈R



We add all the numbers together, and all the variables

1/2(6x-4)-9=0

We multiply all the terms by the denominator


-9*2(6x-4)+1=0

Wy multiply elements

-18x(6+1=0

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