1/2(6x-4)-2/3(12x+12)x=5

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Solution for 1/2(6x-4)-2/3(12x+12)x=5 equation: 


x in (-oo:+oo)

(1/2)*(6*x-4)-((2/3)*x*(12*x+12)) = 5 // - 5

(1/2)*(6*x-4)-((2/3)*x*(12*x+12))-5 = 0

(1/2)*(6*x-4)+(-2/3)*x*(12*x+12)-5 = 0

1/2*(6*x-4)-2/3*x*(12*x+12)-5 = 0

1/2*(6*x-4)-2/3*x*(12*x+12)-5 = 0

-8*x^2-5*x-5-2 = 0

-8*x^2-5*x-7 = 0

-8*x^2-5*x-7 = 0

-1*(8*x^2+5*x+7) = 0

8*x^2+5*x+7 = 0

DELTA = 5^2-(4*7*8)

DELTA = -199

DELTA < 0

-1 = 0

-1 = 0

x belongs to the empty set

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