1/2(6x-4)=-3/4(12x+8)

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Solution for 1/2(6x-4)=-3/4(12x+8) equation: 



1/2(6x-4)=-3/4(12x+8)

We move all terms to the left:

1/2(6x-4)-(-3/4(12x+8))=0



Domain of the equation: 2(6x-4)!=0

x∈R





Domain of the equation: 4(12x+8))!=0

x∈R



We calculate fractions


(4x1/(2(6x-4)*4(12x+8)))+(-(-6x6)/(2(6x-4)*4(12x+8)))=0



We calculate terms in parentheses: +(4x1/(2(6x-4)*4(12x+8))), so:

4x1/(2(6x-4)*4(12x+8))

We multiply all the terms by the denominator


4x1

We add all the numbers together, and all the variables

4x

Back to the equation:

+(4x)





We calculate terms in parentheses: +(-(-6x6)/(2(6x-4)*4(12x+8))), so:

-(-6x6)/(2(6x-4)*4(12x+8))

We add all the numbers together, and all the variables

-(-6x^6)/(2(6x-4)*4(12x+8))

We multiply all the terms by the denominator


-(-6x^6)

We do not support expression: x^6

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