1/2(6x-4)=1/3(12x+9)

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Solution for 1/2(6x-4)=1/3(12x+9) equation:



1/2(6x-4)=1/3(12x+9)
We move all terms to the left:
1/2(6x-4)-(1/3(12x+9))=0
Domain of the equation: 2(6x-4)!=0
x∈R
Domain of the equation: 3(12x+9))!=0
x∈R
We calculate fractions
(3x1/(2(6x-4)*3(12x+9)))+(-2x6/(2(6x-4)*3(12x+9)))=0
We calculate terms in parentheses: +(3x1/(2(6x-4)*3(12x+9))), so:
3x1/(2(6x-4)*3(12x+9))
We multiply all the terms by the denominator
3x1
We add all the numbers together, and all the variables
3x
Back to the equation:
+(3x)
We calculate terms in parentheses: +(-2x6/(2(6x-4)*3(12x+9))), so:
-2x6/(2(6x-4)*3(12x+9))
We multiply all the terms by the denominator
-2x6
We add all the numbers together, and all the variables
-2x^6
We do not support expression: x^6

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