1/2(6x-8)+3(x+2)=(2x-1)

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Solution for 1/2(6x-8)+3(x+2)=(2x-1) equation: 



1/2(6x-8)+3(x+2)=(2x-1)

We move all terms to the left:

1/2(6x-8)+3(x+2)-((2x-1))=0



Domain of the equation: 2(6x-8)!=0

x∈R



We multiply parentheses

1/2(6x-8)+3x-((2x-1))+6=0

We multiply all the terms by the denominator


3x*2(6x-8)-(((2x-1)))*2(6x-8)+6*2(6x-8)+1=0



We calculate terms in parentheses: -(((2x-1)))*2(6x-8), so:

((2x-1)))*2(6x-8



Wy multiply elements

6x^2(6-(((2x-1)))*2(6x-8)+12x(6+1=0

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