1/2(6x-8)2x=1/4(12x-16)

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Solution for 1/2(6x-8)2x=1/4(12x-16) equation: 



1/2(6x-8)2x=1/4(12x-16)

We move all terms to the left:

1/2(6x-8)2x-(1/4(12x-16))=0



Domain of the equation: 2(6x-8)2x!=0

x∈R





Domain of the equation: 4(12x-16))!=0

x∈R



We calculate fractions


(4x1/(2(6x-8)2x*4(12x-16)))+(-(1*2(6x-8)2x)/(2(6x-8)2x*4(12x-16)))=0



We calculate terms in parentheses: +(4x1/(2(6x-8)2x*4(12x-16))), so:

4x1/(2(6x-8)2x*4(12x-16))

We multiply all the terms by the denominator


4x1

We add all the numbers together, and all the variables

4x

Back to the equation:

+(4x)





We calculate terms in parentheses: +(-(1*2(6x-8)2x)/(2(6x-8)2x*4(12x-16))), so:

-(1*2(6x-8)2x)/(2(6x-8)2x*4(12x-16))

We multiply all the terms by the denominator


-(1*2(6x-8)2x)



We calculate terms in parentheses: -(1*2(6x-8)2x), so:

1*2(6x-8)2x

Wy multiply elements

2x(6

Back to the equation:

-(2x(6)



Back to the equation:

+(-(2x6)

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