1/2(6x-8)=7/5(x-5)=1/5

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Solution for 1/2(6x-8)=7/5(x-5)=1/5 equation: 



1/2(6x-8)=7/5(x-5)=1/5

We move all terms to the left:

1/2(6x-8)-(7/5(x-5))=0



Domain of the equation: 2(6x-8)!=0

x∈R





Domain of the equation: 5(x-5))!=0

x∈R



We calculate fractions


(5xx/(2(6x-8)*5(x-5)))+(-14x6/(2(6x-8)*5(x-5)))=0



We calculate terms in parentheses: +(5xx/(2(6x-8)*5(x-5))), so:

5xx/(2(6x-8)*5(x-5))

We multiply all the terms by the denominator


5xx

Back to the equation:

+(5xx)





We calculate terms in parentheses: +(-14x6/(2(6x-8)*5(x-5))), so:

-14x6/(2(6x-8)*5(x-5))

We multiply all the terms by the denominator


-14x6

We add all the numbers together, and all the variables

-14x^6

We do not support expression: x^6

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