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1/2(6y+6)-7=-1/3(3y-12)
We move all terms to the left:
1/2(6y+6)-7-(-1/3(3y-12))=0
Domain of the equation: 2(6y+6)!=0
y∈R
Domain of the equation: 3(3y-12))!=0We calculate fractions
y∈R
(3y3/(2(6y+6)*3(3y-12)))+(-(-2y6)/(2(6y+6)*3(3y-12)))-7=0
We calculate terms in parentheses: +(3y3/(2(6y+6)*3(3y-12))), so:
3y3/(2(6y+6)*3(3y-12))
We multiply all the terms by the denominator
3y3
We add all the numbers together, and all the variables
3y^3
We do not support eypression: y^3
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