1/2(6y+6)-7=-1/3(3y-12)

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Solution for 1/2(6y+6)-7=-1/3(3y-12) equation: 



1/2(6y+6)-7=-1/3(3y-12)

We move all terms to the left:

1/2(6y+6)-7-(-1/3(3y-12))=0



Domain of the equation: 2(6y+6)!=0

y∈R





Domain of the equation: 3(3y-12))!=0

y∈R



We calculate fractions


(3y3/(2(6y+6)*3(3y-12)))+(-(-2y6)/(2(6y+6)*3(3y-12)))-7=0



We calculate terms in parentheses: +(3y3/(2(6y+6)*3(3y-12))), so:

3y3/(2(6y+6)*3(3y-12))

We multiply all the terms by the denominator


3y3

We add all the numbers together, and all the variables

3y^3

We do not support eypression: y^3

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