1/2(6y-8)=-1/3(12-9y)

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Solution for 1/2(6y-8)=-1/3(12-9y) equation:



1/2(6y-8)=-1/3(12-9y)
We move all terms to the left:
1/2(6y-8)-(-1/3(12-9y))=0
Domain of the equation: 2(6y-8)!=0
y∈R
Domain of the equation: 3(12-9y))!=0
y∈R
We add all the numbers together, and all the variables
1/2(6y-8)-(-1/3(-9y+12))=0
We calculate fractions
(3y(-)/(2(6y-8)*3(-9y+12)))+(-(-2y6)/(2(6y-8)*3(-9y+12)))=0
We calculate terms in parentheses: +(3y(-)/(2(6y-8)*3(-9y+12))), so:
3y(-)/(2(6y-8)*3(-9y+12))
We add all the numbers together, and all the variables
3y0/(2(6y-8)*3(-9y+12))
We multiply all the terms by the denominator
3y0
We add all the numbers together, and all the variables
3y
Back to the equation:
+(3y)
We calculate terms in parentheses: +(-(-2y6)/(2(6y-8)*3(-9y+12))), so:
-(-2y6)/(2(6y-8)*3(-9y+12))
We add all the numbers together, and all the variables
-(-2y^6)/(2(6y-8)*3(-9y+12))
We multiply all the terms by the denominator
-(-2y^6)
We do not support eypression: y^6

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