1/2(7y-4)=y=3y-1/2(6-5y)

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Solution for 1/2(7y-4)=y=3y-1/2(6-5y) equation: 



1/2(7y-4)=y=3y-1/2(6-5y)

We move all terms to the left:

1/2(7y-4)-(y)=0



Domain of the equation: 2(7y-4)!=0

y∈R



We add all the numbers together, and all the variables

-1y+1/2(7y-4)=0

We multiply all the terms by the denominator


-1y*2(7y-4)+1=0

Wy multiply elements

-2y^2(7+1=0

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