1/2(8-4x)=13-3x+7x

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Solution for 1/2(8-4x)=13-3x+7x equation: 



1/2(8-4x)=13-3x+7x

We move all terms to the left:

1/2(8-4x)-(13-3x+7x)=0



Domain of the equation: 2(8-4x)!=0

x∈R



We add all the numbers together, and all the variables

1/2(-4x+8)-(4x+13)=0

We get rid of parentheses

1/2(-4x+8)-4x-13=0

We multiply all the terms by the denominator


-4x*2(-4x+8)-13*2(-4x+8)+1=0

Wy multiply elements

-8x^2(--26x(-+1=0

We use the square of the difference formula

-8x^2(+26x(-1=0

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