1/2(8a-20)=2(a+17)

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Solution for 1/2(8a-20)=2(a+17) equation: 



1/2(8a-20)=2(a+17)

We move all terms to the left:

1/2(8a-20)-(2(a+17))=0



Domain of the equation: 2(8a-20)!=0

a∈R



We multiply all the terms by the denominator


-((2(a+17)))*2(8a-20)+1=0



We calculate terms in parentheses: -((2(a+17)))*2(8a-20), so:

(2(a+17)))*2(8a-20





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(2(a+17)))*2(8a-20





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(2(a+17)))*2(8a-20





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(2(a+17)))*2(8a-20





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(2(a+17)))*2(8a-20





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(2(a+17)))*2(8a-20





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(2(a+17)))*2(8a-20





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(2(a+17)))*2(8a-20





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(2(a+17)))*2(8a-20





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(2(a+17)))*2(8a-20





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(2(a+17)))*2(8a-20





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(2(a+17)))*2(8a-20





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(2(a+17)))*2(8a-20





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(2(a+17)))*2(8a-20





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(2(a+17)))*2(8a-20





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(2(a+17)))*2(8a-20





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(2(a+17)))*2(8a-20





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(2(a+17)))*2(8a-20





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(2(a+17)))*2(8a-20





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We calculate terms in parentheses: -((2(a+17)))*2(8a-20), so:

(2(a+17)))*2(8a-20





We calculate terms in parentheses: -((2(a+17)))*2(8a-20), so:

(2(a+17)))*2(8a-20





We calculate terms in parentheses: -((2(a+17)))*2(8a-20), so:

(2(a+17)))*2(8a-20





We calculate terms in parentheses: -((2(a+17)))*2(8a-20), so:

(2(a+17)))*2(8a-20





We calculate terms in parentheses: -((2(a+17)))*2(8a-20), so:

(2(a+17)))*2(8a-20





We calculate terms in parentheses: -((2(a+17)))*2(8a-20), so:

(2(a+17)))*2(8a-20





We calculate terms in parentheses: -((2(a+17)))*2(8a-20), so:

(2(a+17)))*2(8a-20





We calculate terms in parentheses: -((2(a+17)))*2(8a-20), so:

(2(a+17)))*2(8a-20





We calculate terms in parentheses: -((2(a+17)))*2(8a-20), so:

(2(a+17)))*2(8a-20





We calculate terms in parentheses: -((2(a+17)))*2(8a-20), so:

(2(a+17)))*2(8a-20





We calculate terms in parentheses: -((2(a+17)))*2(8a-20), so:

(2(a+17)))*2(8a-20





We calculate terms in parentheses: -((2(a+17)))*2(8a-20), so:

(2(a+17)))*2(8a-20





We calculate terms in parentheses: -((2(a+17)))*2(8a-20), so:

(2(a+17)))*2(8a-20





We calculate terms in parentheses: -((2(a+17)))*2(8a-20), so:

(2(a+17)))*2(8a-20





We calculate terms in parentheses: -((2(a+17)))*2(8a-20), so:

(2(a+17)))*2(8a-20





We calculate terms in parentheses: -((2(a+17)))*2(8a-20), so:

(2(a+17)))*2(8a-20





We calculate terms in parentheses: -((2(a+17)))*2(8a-20), so:

(2(a+17)))*2(8a-20



We move all terms containing a to the left, all other terms to the right

-((2(a+17)))*2(8a-20)=-1

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