1/2(8b+10)+3b=2(7b-8)

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Solution for 1/2(8b+10)+3b=2(7b-8) equation: 



1/2(8b+10)+3b=2(7b-8)

We move all terms to the left:

1/2(8b+10)+3b-(2(7b-8))=0



Domain of the equation: 2(8b+10)!=0

b∈R



We add all the numbers together, and all the variables

3b+1/2(8b+10)-(2(7b-8))=0

We multiply all the terms by the denominator


3b*2(8b+10)-((2(7b-8)))*2(8b+10)+1=0



We calculate terms in parentheses: -((2(7b-8)))*2(8b+10), so:

(2(7b-8)))*2(8b+10



Wy multiply elements

6b^2(8-((2(7b-8)))*2(8b+10)+1=0

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