1/2(8b+20)=1/3(18b+6)

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Solution for 1/2(8b+20)=1/3(18b+6) equation: 



1/2(8b+20)=1/3(18b+6)

We move all terms to the left:

1/2(8b+20)-(1/3(18b+6))=0



Domain of the equation: 2(8b+20)!=0

b∈R





Domain of the equation: 3(18b+6))!=0

b∈R



We calculate fractions


(3b1/(2(8b+20)*3(18b+6)))+(-2b8/(2(8b+20)*3(18b+6)))=0



We calculate terms in parentheses: +(3b1/(2(8b+20)*3(18b+6))), so:

3b1/(2(8b+20)*3(18b+6))

We multiply all the terms by the denominator


3b1

We add all the numbers together, and all the variables

3b

Back to the equation:

+(3b)





We calculate terms in parentheses: +(-2b8/(2(8b+20)*3(18b+6))), so:

-2b8/(2(8b+20)*3(18b+6))

We multiply all the terms by the denominator


-2b8

We add all the numbers together, and all the variables

-2b^8

We do not support ebpression: b^8

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