1/2(8m+4)+2=1/3(18m-18)

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Solution for 1/2(8m+4)+2=1/3(18m-18) equation:



1/2(8m+4)+2=1/3(18m-18)
We move all terms to the left:
1/2(8m+4)+2-(1/3(18m-18))=0
Domain of the equation: 2(8m+4)!=0
m∈R
Domain of the equation: 3(18m-18))!=0
m∈R
We calculate fractions
(3m1/(2(8m+4)*3(18m-18)))+(-2m8/(2(8m+4)*3(18m-18)))+2=0
We calculate terms in parentheses: +(3m1/(2(8m+4)*3(18m-18))), so:
3m1/(2(8m+4)*3(18m-18))
We multiply all the terms by the denominator
3m1
We add all the numbers together, and all the variables
3m
Back to the equation:
+(3m)
We calculate terms in parentheses: +(-2m8/(2(8m+4)*3(18m-18))), so:
-2m8/(2(8m+4)*3(18m-18))
We multiply all the terms by the denominator
-2m8
We add all the numbers together, and all the variables
-2m^8
We do not support empression: m^8

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