1/2(8x+10)+1=1/3(6x-3)+7

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Solution for 1/2(8x+10)+1=1/3(6x-3)+7 equation: 



1/2(8x+10)+1=1/3(6x-3)+7

We move all terms to the left:

1/2(8x+10)+1-(1/3(6x-3)+7)=0



Domain of the equation: 2(8x+10)!=0

x∈R





Domain of the equation: 3(6x-3)+7)!=0

x∈R



We calculate fractions


(3x6/(2(8x+10)*3(6x-3))+(-2x8/(2(8x+10)*3(6x-3))+1=0

We can not solve this equation

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