1/2(8x+4)=2(2x+1)

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Solution for 1/2(8x+4)=2(2x+1) equation: 



1/2(8x+4)=2(2x+1)

We move all terms to the left:

1/2(8x+4)-(2(2x+1))=0



Domain of the equation: 2(8x+4)!=0

x∈R



We multiply all the terms by the denominator


-((2(2x+1)))*2(8x+4)+1=0



We calculate terms in parentheses: -((2(2x+1)))*2(8x+4), so:

(2(2x+1)))*2(8x+4





We calculate terms in parentheses: -((2(2x+1)))*2(8x+4), so:

(2(2x+1)))*2(8x+4





We calculate terms in parentheses: -((2(2x+1)))*2(8x+4), so:

(2(2x+1)))*2(8x+4





We calculate terms in parentheses: -((2(2x+1)))*2(8x+4), so:

(2(2x+1)))*2(8x+4





We calculate terms in parentheses: -((2(2x+1)))*2(8x+4), so:

(2(2x+1)))*2(8x+4





We calculate terms in parentheses: -((2(2x+1)))*2(8x+4), so:

(2(2x+1)))*2(8x+4





We calculate terms in parentheses: -((2(2x+1)))*2(8x+4), so:

(2(2x+1)))*2(8x+4





We calculate terms in parentheses: -((2(2x+1)))*2(8x+4), so:

(2(2x+1)))*2(8x+4





We calculate terms in parentheses: -((2(2x+1)))*2(8x+4), so:

(2(2x+1)))*2(8x+4





We calculate terms in parentheses: -((2(2x+1)))*2(8x+4), so:

(2(2x+1)))*2(8x+4





We calculate terms in parentheses: -((2(2x+1)))*2(8x+4), so:

(2(2x+1)))*2(8x+4





We calculate terms in parentheses: -((2(2x+1)))*2(8x+4), so:

(2(2x+1)))*2(8x+4





We calculate terms in parentheses: -((2(2x+1)))*2(8x+4), so:

(2(2x+1)))*2(8x+4





We calculate terms in parentheses: -((2(2x+1)))*2(8x+4), so:

(2(2x+1)))*2(8x+4





We calculate terms in parentheses: -((2(2x+1)))*2(8x+4), so:

(2(2x+1)))*2(8x+4





We calculate terms in parentheses: -((2(2x+1)))*2(8x+4), so:

(2(2x+1)))*2(8x+4





We calculate terms in parentheses: -((2(2x+1)))*2(8x+4), so:

(2(2x+1)))*2(8x+4





We calculate terms in parentheses: -((2(2x+1)))*2(8x+4), so:

(2(2x+1)))*2(8x+4





We calculate terms in parentheses: -((2(2x+1)))*2(8x+4), so:

(2(2x+1)))*2(8x+4





We calculate terms in parentheses: -((2(2x+1)))*2(8x+4), so:

(2(2x+1)))*2(8x+4





We calculate terms in parentheses: -((2(2x+1)))*2(8x+4), so:

(2(2x+1)))*2(8x+4





We calculate terms in parentheses: -((2(2x+1)))*2(8x+4), so:

(2(2x+1)))*2(8x+4





We calculate terms in parentheses: -((2(2x+1)))*2(8x+4), so:

(2(2x+1)))*2(8x+4





We calculate terms in parentheses: -((2(2x+1)))*2(8x+4), so:

(2(2x+1)))*2(8x+4





We calculate terms in parentheses: -((2(2x+1)))*2(8x+4), so:

(2(2x+1)))*2(8x+4





We calculate terms in parentheses: -((2(2x+1)))*2(8x+4), so:

(2(2x+1)))*2(8x+4





We calculate terms in parentheses: -((2(2x+1)))*2(8x+4), so:

(2(2x+1)))*2(8x+4





We calculate terms in parentheses: -((2(2x+1)))*2(8x+4), so:

(2(2x+1)))*2(8x+4





We calculate terms in parentheses: -((2(2x+1)))*2(8x+4), so:

(2(2x+1)))*2(8x+4





We calculate terms in parentheses: -((2(2x+1)))*2(8x+4), so:

(2(2x+1)))*2(8x+4





We calculate terms in parentheses: -((2(2x+1)))*2(8x+4), so:

(2(2x+1)))*2(8x+4





We calculate terms in parentheses: -((2(2x+1)))*2(8x+4), so:

(2(2x+1)))*2(8x+4





We calculate terms in parentheses: -((2(2x+1)))*2(8x+4), so:

(2(2x+1)))*2(8x+4





We calculate terms in parentheses: -((2(2x+1)))*2(8x+4), so:

(2(2x+1)))*2(8x+4





We calculate terms in parentheses: -((2(2x+1)))*2(8x+4), so:

(2(2x+1)))*2(8x+4





We calculate terms in parentheses: -((2(2x+1)))*2(8x+4), so:

(2(2x+1)))*2(8x+4





We calculate terms in parentheses: -((2(2x+1)))*2(8x+4), so:

(2(2x+1)))*2(8x+4





We calculate terms in parentheses: -((2(2x+1)))*2(8x+4), so:

(2(2x+1)))*2(8x+4





We calculate terms in parentheses: -((2(2x+1)))*2(8x+4), so:

(2(2x+1)))*2(8x+4





We calculate terms in parentheses: -((2(2x+1)))*2(8x+4), so:

(2(2x+1)))*2(8x+4





We calculate terms in parentheses: -((2(2x+1)))*2(8x+4), so:

(2(2x+1)))*2(8x+4





We calculate terms in parentheses: -((2(2x+1)))*2(8x+4), so:

(2(2x+1)))*2(8x+4





We calculate terms in parentheses: -((2(2x+1)))*2(8x+4), so:

(2(2x+1)))*2(8x+4





							

									
									
									
									
									
									

														
			

			
				

						
				
				
					
			
						
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