1/2(8x+6)+2x=3(x-4)

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Solution for 1/2(8x+6)+2x=3(x-4) equation: 



1/2(8x+6)+2x=3(x-4)

We move all terms to the left:

1/2(8x+6)+2x-(3(x-4))=0



Domain of the equation: 2(8x+6)!=0

x∈R



We add all the numbers together, and all the variables

2x+1/2(8x+6)-(3(x-4))=0

We multiply all the terms by the denominator


2x*2(8x+6)-((3(x-4)))*2(8x+6)+1=0



We calculate terms in parentheses: -((3(x-4)))*2(8x+6), so:

(3(x-4)))*2(8x+6



Wy multiply elements

4x^2(8-((3(x-4)))*2(8x+6)+1=0

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