1/2(8x-10)=1/5(25x-20)

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Solution for 1/2(8x-10)=1/5(25x-20) equation: 



1/2(8x-10)=1/5(25x-20)

We move all terms to the left:

1/2(8x-10)-(1/5(25x-20))=0



Domain of the equation: 2(8x-10)!=0

x∈R





Domain of the equation: 5(25x-20))!=0

x∈R



We calculate fractions


(5x2/(2(8x-10)*5(25x-20)))+(-2x8/(2(8x-10)*5(25x-20)))=0



We calculate terms in parentheses: +(5x2/(2(8x-10)*5(25x-20))), so:

5x2/(2(8x-10)*5(25x-20))

We multiply all the terms by the denominator


5x2

We add all the numbers together, and all the variables

5x^2

Back to the equation:

+(5x^2)





We calculate terms in parentheses: +(-2x8/(2(8x-10)*5(25x-20))), so:

-2x8/(2(8x-10)*5(25x-20))

We multiply all the terms by the denominator


-2x8

We add all the numbers together, and all the variables

-2x^8

We do not support expression: x^8

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