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1/2(8x-10)=2(10+2x)
We move all terms to the left:
1/2(8x-10)-(2(10+2x))=0
Domain of the equation: 2(8x-10)!=0We add all the numbers together, and all the variables
x∈R
1/2(8x-10)-(2(2x+10))=0
We multiply all the terms by the denominator
-((2(2x+10)))*2(8x-10)+1=0
We calculate terms in parentheses: -((2(2x+10)))*2(8x-10), so:
(2(2x+10)))*2(8x-10
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(2(2x+10)))*2(8x-10
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(2(2x+10)))*2(8x-10
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(2(2x+10)))*2(8x-10
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(2(2x+10)))*2(8x-10
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(2(2x+10)))*2(8x-10
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(2(2x+10)))*2(8x-10
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(2(2x+10)))*2(8x-10
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We calculate terms
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