1/2(8x-10)=6x+3x-55

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Solution for 1/2(8x-10)=6x+3x-55 equation: 



1/2(8x-10)=6x+3x-55

We move all terms to the left:

1/2(8x-10)-(6x+3x-55)=0



Domain of the equation: 2(8x-10)!=0

x∈R



We add all the numbers together, and all the variables

1/2(8x-10)-(9x-55)=0

We get rid of parentheses

1/2(8x-10)-9x+55=0

We multiply all the terms by the denominator


-9x*2(8x-10)+55*2(8x-10)+1=0

Wy multiply elements

-18x^2(8+110x(8+1=0

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