1/2(8x-12)=1/3(6x+6)

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Solution for 1/2(8x-12)=1/3(6x+6) equation: 



1/2(8x-12)=1/3(6x+6)

We move all terms to the left:

1/2(8x-12)-(1/3(6x+6))=0



Domain of the equation: 2(8x-12)!=0

x∈R





Domain of the equation: 3(6x+6))!=0

x∈R



We calculate fractions


(3x6/(2(8x-12)*3(6x+6)))+(-2x8/(2(8x-12)*3(6x+6)))=0



We calculate terms in parentheses: +(3x6/(2(8x-12)*3(6x+6))), so:

3x6/(2(8x-12)*3(6x+6))

We multiply all the terms by the denominator


3x6

We add all the numbers together, and all the variables

3x^6

We do not support expression: x^6

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