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1/2(8x-16)=2/3(6x+12)
We move all terms to the left:
1/2(8x-16)-(2/3(6x+12))=0
Domain of the equation: 2(8x-16)!=0
x∈R
Domain of the equation: 3(6x+12))!=0We calculate fractions
x∈R
(3x6/(2(8x-16)*3(6x+12)))+(-4x8/(2(8x-16)*3(6x+12)))=0
We calculate terms in parentheses: +(3x6/(2(8x-16)*3(6x+12))), so:
3x6/(2(8x-16)*3(6x+12))
We multiply all the terms by the denominator
3x6
We add all the numbers together, and all the variables
3x^6
We do not support expression: x^6
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