1/2(8x-20)-16=10x+51

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Solution for 1/2(8x-20)-16=10x+51 equation: 



1/2(8x-20)-16=10x+51

We move all terms to the left:

1/2(8x-20)-16-(10x+51)=0



Domain of the equation: 2(8x-20)!=0

x∈R



We get rid of parentheses

1/2(8x-20)-10x-51-16=0

We multiply all the terms by the denominator


-10x*2(8x-20)-51*2(8x-20)-16*2(8x-20)+1=0

Wy multiply elements

-20x^2(8-102x(8-32x(8+1=0

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