1/2(8x-20)=1/4(12x+32)

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Solution for 1/2(8x-20)=1/4(12x+32) equation: 



1/2(8x-20)=1/4(12x+32)

We move all terms to the left:

1/2(8x-20)-(1/4(12x+32))=0



Domain of the equation: 2(8x-20)!=0

x∈R





Domain of the equation: 4(12x+32))!=0

x∈R



We calculate fractions


(4x1/(2(8x-20)*4(12x+32)))+(-2x8/(2(8x-20)*4(12x+32)))=0



We calculate terms in parentheses: +(4x1/(2(8x-20)*4(12x+32))), so:

4x1/(2(8x-20)*4(12x+32))

We multiply all the terms by the denominator


4x1

We add all the numbers together, and all the variables

4x

Back to the equation:

+(4x)





We calculate terms in parentheses: +(-2x8/(2(8x-20)*4(12x+32))), so:

-2x8/(2(8x-20)*4(12x+32))

We multiply all the terms by the denominator


-2x8

We add all the numbers together, and all the variables

-2x^8

We do not support expression: x^8

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