1/2(9-3x)=3-3/x

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Solution for 1/2(9-3x)=3-3/x equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(1/2)*(9-(3*x)) = 3-(3/x) // - 3-(3/x)

(1/2)*(9-(3*x))+3/x-3 = 0

(1/2)*(9-3*x)+3/x-3 = 0

1/2*(9-3*x)+3/x-3 = 0

(1/2*x*(9-3*x))/x+3/x+(-3*x)/x = 0

1/2*x*(9-3*x)-3*x+3 = 0

9/2*x-3/2*x^2-3*x+3 = 0

3/2*x-3/2*x^2+3 = 0

3/2*x-3/2*x^2+3 = 0

3*(1/2*x-1/2*x^2+1) = 0

1/2*x-1/2*x^2+1 = 0

DELTA = (1/2)^2-(-1/2*1*4)

DELTA = 9/4

DELTA > 0

x = ((9/4)^(1/2)-1/2)/(-1/2*2) or x = (-(9/4)^(1/2)-1/2)/(-1/2*2)

x = -1 or x = 2

3*(x+1)*(x-2) = 0

(3*(x+1)*(x-2))/x = 0

(3*(x+1)*(x-2))/x = 0 // * x

3*(x+1)*(x-2) = 0

( 3 )

3 = 0

x belongs to the empty set

( x+1 )

x+1 = 0 // - 1

x = -1

( x-2 )

x-2 = 0 // + 2

x = 2

x in { -1, 2 }

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