1/2(a+2)=1/7(8-a)

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Solution for 1/2(a+2)=1/7(8-a) equation: 



1/2(a+2)=1/7(8-a)

We move all terms to the left:

1/2(a+2)-(1/7(8-a))=0



Domain of the equation: 2(a+2)!=0

a∈R





Domain of the equation: 7(8-a))!=0

a∈R



We add all the numbers together, and all the variables

1/2(a+2)-(1/7(-1a+8))=0

We calculate fractions


(7a(-)/(2(a+2)*7(-1a+8)))+(-2aa/(2(a+2)*7(-1a+8)))=0



We calculate terms in parentheses: +(7a(-)/(2(a+2)*7(-1a+8))), so:

7a(-)/(2(a+2)*7(-1a+8))

We add all the numbers together, and all the variables

7a0/(2(a+2)*7(-1a+8))

We multiply all the terms by the denominator


7a0

We add all the numbers together, and all the variables

7a

Back to the equation:

+(7a)





We calculate terms in parentheses: +(-2aa/(2(a+2)*7(-1a+8))), so:

-2aa/(2(a+2)*7(-1a+8))

We multiply all the terms by the denominator


-2aa

Back to the equation:

+(-2aa)



We get rid of parentheses

7a-2aa=0

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