1/2(b+2)+3b=29

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Solution for 1/2(b+2)+3b=29 equation: 



1/2(b+2)+3b=29

We move all terms to the left:

1/2(b+2)+3b-(29)=0



Domain of the equation: 2(b+2)!=0

b∈R



We add all the numbers together, and all the variables

3b+1/2(b+2)-29=0

We multiply all the terms by the denominator


3b*2(b+2)-29*2(b+2)+1=0

Wy multiply elements

6b^2(b-58b(b+1=0

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