1/2(b+3)=2b+3

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Solution for 1/2(b+3)=2b+3 equation:



1/2(b+3)=2b+3
We move all terms to the left:
1/2(b+3)-(2b+3)=0
Domain of the equation: 2(b+3)!=0
b∈R
We get rid of parentheses
1/2(b+3)-2b-3=0
We multiply all the terms by the denominator
-2b*2(b+3)-3*2(b+3)+1=0
Wy multiply elements
-4b^2(b-6b(b+1=0

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