1/2(b+3)=2b+3

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Solution for 1/2(b+3)=2b+3 equation: 



1/2(b+3)=2b+3

We move all terms to the left:

1/2(b+3)-(2b+3)=0



Domain of the equation: 2(b+3)!=0

b∈R



We get rid of parentheses

1/2(b+3)-2b-3=0

We multiply all the terms by the denominator


-2b*2(b+3)-3*2(b+3)+1=0

Wy multiply elements

-4b^2(b-6b(b+1=0

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