1/2(b-2)=1/6(2b+4)

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Solution for 1/2(b-2)=1/6(2b+4) equation: 



1/2(b-2)=1/6(2b+4)

We move all terms to the left:

1/2(b-2)-(1/6(2b+4))=0



Domain of the equation: 2(b-2)!=0

b∈R





Domain of the equation: 6(2b+4))!=0

b∈R



We calculate fractions


(6b2/(2(b-2)*6(2b+4)))+(-2bb/(2(b-2)*6(2b+4)))=0



We calculate terms in parentheses: +(6b2/(2(b-2)*6(2b+4))), so:

6b2/(2(b-2)*6(2b+4))

We multiply all the terms by the denominator


6b2

We add all the numbers together, and all the variables

6b^2

Back to the equation:

+(6b^2)





We calculate terms in parentheses: +(-2bb/(2(b-2)*6(2b+4))), so:

-2bb/(2(b-2)*6(2b+4))

We multiply all the terms by the denominator


-2bb

Back to the equation:

+(-2bb)



We get rid of parentheses

6b^2-2bb=0

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