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1/2(c+5))-10=-4
We move all terms to the left:
1/2(c+5))-10-(-4)=0
Domain of the equation: 2(c+5))-10-(!=0We add all the numbers together, and all the variables
c∈R
1/2(c+5))-10-(=0
We multiply all the terms by the denominator
1!=0
There is no solution for this equation
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