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1/2(d-3)-4/1(5d-5)=5/12
We move all terms to the left:
1/2(d-3)-4/1(5d-5)-(5/12)=0
Domain of the equation: 2(d-3)!=0
d∈R
Domain of the equation: 1(5d-5)!=0We add all the numbers together, and all the variables
d∈R
1/2(d-3)-4/1(5d-5)-(+5/12)=0
We get rid of parentheses
1/2(d-3)-4/1(5d-5)-5/12=0
We calculate fractions
(12d5/(2(d-3)*1(5d-5)*12)+(-96dd/(2(d-3)*1(5d-5)*12)+(-10d^2d/(2(d-3)*1(5d-5)*12)=0
We calculate terms in parentheses: +(12d5/(2(d-3)*1(5d-5)*12)+(-96dd/(2(d-3)*1(5d-5)*12)+(-10d^2d/(2(d-3)*1(5d-5)*12), so:
12d5/(2(d-3)*1(5d-5)*12)+(-96dd/(2(d-3)*1(5d-5)*12)+(-10d^2d/(2(d-3)*1(5d-5)*12
We can not solve this equation
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