1/2(d-3)-7/3(2d-4)=7/12

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Solution for 1/2(d-3)-7/3(2d-4)=7/12 equation: 



1/2(d-3)-7/3(2d-4)=7/12

We move all terms to the left:

1/2(d-3)-7/3(2d-4)-(7/12)=0



Domain of the equation: 2(d-3)!=0

d∈R





Domain of the equation: 3(2d-4)!=0

d∈R



We add all the numbers together, and all the variables

1/2(d-3)-7/3(2d-4)-(+7/12)=0

We get rid of parentheses

1/2(d-3)-7/3(2d-4)-7/12=0

We calculate fractions


(36d2/(2(d-3)*3(2d-4)*12)+(-168dd/(2(d-3)*3(2d-4)*12)+(-42d^2d/(2(d-3)*3(2d-4)*12)=0



We calculate terms in parentheses: +(36d2/(2(d-3)*3(2d-4)*12)+(-168dd/(2(d-3)*3(2d-4)*12)+(-42d^2d/(2(d-3)*3(2d-4)*12), so:

36d2/(2(d-3)*3(2d-4)*12)+(-168dd/(2(d-3)*3(2d-4)*12)+(-42d^2d/(2(d-3)*3(2d-4)*12

We can not solve this equation

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