1/2(d-3)-8/3(2d-5)=7/6

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Solution for 1/2(d-3)-8/3(2d-5)=7/6 equation: 



1/2(d-3)-8/3(2d-5)=7/6

We move all terms to the left:

1/2(d-3)-8/3(2d-5)-(7/6)=0



Domain of the equation: 2(d-3)!=0

d∈R





Domain of the equation: 3(2d-5)!=0

d∈R



We add all the numbers together, and all the variables

1/2(d-3)-8/3(2d-5)-(+7/6)=0

We get rid of parentheses

1/2(d-3)-8/3(2d-5)-7/6=0

We calculate fractions


(18d2/(2(d-3)*3(2d-5)*6)+(-96dd/(2(d-3)*3(2d-5)*6)+(-42d^2d/(2(d-3)*3(2d-5)*6)=0



We calculate terms in parentheses: +(18d2/(2(d-3)*3(2d-5)*6)+(-96dd/(2(d-3)*3(2d-5)*6)+(-42d^2d/(2(d-3)*3(2d-5)*6), so:

18d2/(2(d-3)*3(2d-5)*6)+(-96dd/(2(d-3)*3(2d-5)*6)+(-42d^2d/(2(d-3)*3(2d-5)*6

We can not solve this equation

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