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1/2(d-3)-8/3(4d-4)=5/12
We move all terms to the left:
1/2(d-3)-8/3(4d-4)-(5/12)=0
Domain of the equation: 2(d-3)!=0
d∈R
Domain of the equation: 3(4d-4)!=0We add all the numbers together, and all the variables
d∈R
1/2(d-3)-8/3(4d-4)-(+5/12)=0
We get rid of parentheses
1/2(d-3)-8/3(4d-4)-5/12=0
We calculate fractions
(36d4/(2(d-3)*3(4d-4)*12)+(-192dd/(2(d-3)*3(4d-4)*12)+(-30d^2d/(2(d-3)*3(4d-4)*12)=0
We calculate terms in parentheses: +(36d4/(2(d-3)*3(4d-4)*12)+(-192dd/(2(d-3)*3(4d-4)*12)+(-30d^2d/(2(d-3)*3(4d-4)*12), so:
36d4/(2(d-3)*3(4d-4)*12)+(-192dd/(2(d-3)*3(4d-4)*12)+(-30d^2d/(2(d-3)*3(4d-4)*12
We can not solve this equation
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