1/2(d-7)-5/3(5d-5)=7/6

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Solution for 1/2(d-7)-5/3(5d-5)=7/6 equation:



1/2(d-7)-5/3(5d-5)=7/6
We move all terms to the left:
1/2(d-7)-5/3(5d-5)-(7/6)=0
Domain of the equation: 2(d-7)!=0
d∈R
Domain of the equation: 3(5d-5)!=0
d∈R
We add all the numbers together, and all the variables
1/2(d-7)-5/3(5d-5)-(+7/6)=0
We get rid of parentheses
1/2(d-7)-5/3(5d-5)-7/6=0
We calculate fractions
(18d5/(2(d-7)*3(5d-5)*6)+(-60dd/(2(d-7)*3(5d-5)*6)+(-42d^2d/(2(d-7)*3(5d-5)*6)=0
We calculate terms in parentheses: +(18d5/(2(d-7)*3(5d-5)*6)+(-60dd/(2(d-7)*3(5d-5)*6)+(-42d^2d/(2(d-7)*3(5d-5)*6), so:
18d5/(2(d-7)*3(5d-5)*6)+(-60dd/(2(d-7)*3(5d-5)*6)+(-42d^2d/(2(d-7)*3(5d-5)*6
We can not solve this equation

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