1/2(g-11)(g-8)=35

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Solution for 1/2(g-11)(g-8)=35 equation: 



1/2(g-11)(g-8)=35

We move all terms to the left:

1/2(g-11)(g-8)-(35)=0



Domain of the equation: 2(g-11)(g-8)!=0

g∈R



We multiply parentheses ..

1/2(+g^2-8g-11g+88)-35=0

We multiply all the terms by the denominator


-35*2(+g^2-8g-11g+88)+1=0

Wy multiply elements

-70g(++1=0

We use the square of the difference formula

-70g(+1=0

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