1/2(k-3)=1/3(k+16)

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Solution for 1/2(k-3)=1/3(k+16) equation: 



1/2(k-3)=1/3(k+16)

We move all terms to the left:

1/2(k-3)-(1/3(k+16))=0



Domain of the equation: 2(k-3)!=0

k∈R





Domain of the equation: 3(k+16))!=0

k∈R



We calculate fractions


(3kk/(2(k-3)*3(k+16)))+(-2kk/(2(k-3)*3(k+16)))=0



We calculate terms in parentheses: +(3kk/(2(k-3)*3(k+16))), so:

3kk/(2(k-3)*3(k+16))

We multiply all the terms by the denominator


3kk

Back to the equation:

+(3kk)





We calculate terms in parentheses: +(-2kk/(2(k-3)*3(k+16))), so:

-2kk/(2(k-3)*3(k+16))

We multiply all the terms by the denominator


-2kk

Back to the equation:

+(-2kk)



We get rid of parentheses

3kk-2kk=0

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