1/2(m-1)+5=1/3(2m+1)

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Solution for 1/2(m-1)+5=1/3(2m+1) equation: 



1/2(m-1)+5=1/3(2m+1)

We move all terms to the left:

1/2(m-1)+5-(1/3(2m+1))=0



Domain of the equation: 2(m-1)!=0

m∈R





Domain of the equation: 3(2m+1))!=0

m∈R



We calculate fractions


(3m2/(2(m-1)*3(2m+1)))+(-2mm/(2(m-1)*3(2m+1)))+5=0



We calculate terms in parentheses: +(3m2/(2(m-1)*3(2m+1))), so:

3m2/(2(m-1)*3(2m+1))

We multiply all the terms by the denominator


3m2

We add all the numbers together, and all the variables

3m^2

Back to the equation:

+(3m^2)





We calculate terms in parentheses: +(-2mm/(2(m-1)*3(2m+1))), so:

-2mm/(2(m-1)*3(2m+1))

We multiply all the terms by the denominator


-2mm

Back to the equation:

+(-2mm)



We get rid of parentheses

3m^2-2mm+5=0

We move all terms containing m to the left, all other terms to the right

3m^2-2mm=-5

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