1/2(n-1)+1/3(n-2)+1/4(n-3)=23

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Solution for 1/2(n-1)+1/3(n-2)+1/4(n-3)=23 equation: 



1/2(n-1)+1/3(n-2)+1/4(n-3)=23

We move all terms to the left:

1/2(n-1)+1/3(n-2)+1/4(n-3)-(23)=0



Domain of the equation: 2(n-1)!=0

n∈R





Domain of the equation: 3(n-2)!=0

n∈R





Domain of the equation: 4(n-3)!=0

n∈R



We calculate fractions

We do not support enpression: n^2(n

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