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1/2(n-4)-3=3-(2n=3)
We move all terms to the left:
1/2(n-4)-3-(3-(2n)=0
Domain of the equation: 2(n-4)!=0We multiply all the terms by the denominator
n∈R
-((3-2n-3)*2(n-4)+1=0
We add all the numbers together, and all the variables
-((-2n)*2(n-4)+1=0
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